How a proof by contradiction works

So, we want to show that p is true.

In a proof by contradiction, we start out by saying:

We then show that this leads to a contradiction, a statement like (q ∧ ¬q)

That is, we show that ¬p→(q ∧ ¬q), where (q ∧ ¬q) is some contradiction

But, how does this allow us to conclude that p is true?

Well, we know that (q ∧ ¬q) is always false. Thus if we show that ¬p→(q ∧ ¬q), we have shown that ¬p→F.

That is, we have shown that (¬p→F) is a true statement.

And we know that ab is equivalent to writing ¬a b

Thus if (¬p→F) is true, then (¬(¬p ) ∨ F) is true, i.e. ( p ∨ F) is true

By the identity law ( p ∨ F) ≡ p we have that p is true.

By now, you should see that these tables on p. 24 and 25 are pretty handy. If you haven't read through the textbook sections that surround these tables, now would be a good time to do that.


Some links to discussions of proof by contradiction:


P. Conrad, 04/09/2008